¿Cómo se resuelven estos logaritmos?

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Hola Víctor!

6)

a)

$$\begin{align}&-2,15=log_a(B·D)=log_aB+log_aD\\&\\&==>\\&\\&log_aD=-2,15-log_aB=-2,15-30,14=-32,29\\&\\&b)\\&1,03= log_a \Big( \frac P B \Big)=log_aP-log_aB\\&\\&==>\\&\\&log_aP=1,03+log_aB=1,03+30,14=31,17\\&\\&==>\\&log_aP^2=2log_aP=2(31,17)=62,34\end{align}$$

24)

a)

$$\begin{align}&log_ab·log_ba= \frac{log_b b}{log_b a}·log_b a=log_b b· \frac{log_b a}{log_b a}=1·1=1\\&\\&b)\\&lnx=\frac{logx}{log e}=\frac{logx}{0,434294481}=2,302585093logx\\&\\&c)\\&log_2 x= \frac{log x}{log 2}=3,3219 log x\end{align}$$

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