Ayuda urgente
Gracias anticipadas favor ayudarme a resolver:
2x al cubo -2x al cuadrado -5=0.
Saludos cordiales
2x al cubo -2x al cuadrado -5=0.
Saludos cordiales
1 respuesta
Respuesta
1
Esta ecuación cúbica es de compleja solución. La he resuelto mediante un software de análisis matemático que ofrece los siguientes resultados, los cuales satisfacen la ecuación (son correctos):
x1 = 1/6*(278+6*2145^(1/2))^(1/3)+2/3/(278+6*2145^(1/2))^(1/3)+1/3 = 1,784802
x2 = -1/12*(278+6*2145^(1/2))^(1/3)-1/3/(278+6*2145^(1/2))^(1/3)+1/3+1/2*i*3^(1/2)*(1/6*(278+6*2145^(1/2))^(1/3)-2/3/(278+6*2145^(1/2))^(1/3)) = 0,3924 +1,1166*i
x3 =-1/12*(278+6*2145^(1/2))^(1/3)-1/3/(278+6*2145^(1/2))^(1/3)+1/3-1/2*i*3^(1/2)*(1/6*(278+6*2145^(1/2))^(1/3)-2/3/(278+6*2145^(1/2))^(1/3)) = 0,3924 +1,1166*i
x1 = 1/6*(278+6*2145^(1/2))^(1/3)+2/3/(278+6*2145^(1/2))^(1/3)+1/3 = 1,784802
x2 = -1/12*(278+6*2145^(1/2))^(1/3)-1/3/(278+6*2145^(1/2))^(1/3)+1/3+1/2*i*3^(1/2)*(1/6*(278+6*2145^(1/2))^(1/3)-2/3/(278+6*2145^(1/2))^(1/3)) = 0,3924 +1,1166*i
x3 =-1/12*(278+6*2145^(1/2))^(1/3)-1/3/(278+6*2145^(1/2))^(1/3)+1/3-1/2*i*3^(1/2)*(1/6*(278+6*2145^(1/2))^(1/3)-2/3/(278+6*2145^(1/2))^(1/3)) = 0,3924 +1,1166*i