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5x^2 + 12x + 7 Y 3x^2 -11 x -12
5x^2 + 12x + 7 Y 3x^2 -11 x -12
1 respuesta
Respuesta de canalrev
1
No se bien lo que quieres que haga, supongo que calcular las raíces de los polinomios, sino es así dímelo.
5x^2 + 12x + 7=0
x=(-12+-(144-4·5·7)^(1/2))/(2·5)=(-12+-2)/10 -> x=-1 x=-7/5
5x^2 + 12x + 7=5·(x+1)·(x+7/5)
3x^2 -11 x -12=0
x=(11+-(121-4·3·(-12))^(1/2))/(2·3)=(11+-(165)^(1/2))/6
--> x=(11+(165)^(1/2))/6 x=(11-(165)^(1/2))/6
3x^2 -11 x -12=(x-(11+(165)^(1/2))/6)·(x-(11-(165)^(1/2))/6)
5x^2 + 12x + 7=0
x=(-12+-(144-4·5·7)^(1/2))/(2·5)=(-12+-2)/10 -> x=-1 x=-7/5
5x^2 + 12x + 7=5·(x+1)·(x+7/5)
3x^2 -11 x -12=0
x=(11+-(121-4·3·(-12))^(1/2))/(2·3)=(11+-(165)^(1/2))/6
--> x=(11+(165)^(1/2))/6 x=(11-(165)^(1/2))/6
3x^2 -11 x -12=(x-(11+(165)^(1/2))/6)·(x-(11-(165)^(1/2))/6)