mechanique

pollux_troy respondió: lim x->4 (x+2)/(x-4)= lim (4+2)/(4-4)= lim 6/0 = +oo (infinito) lim x->3/2 (4x²-9)/(2x+3)= lim (4*(9/4)-9)/(2*(3/2)+3)= lim 0/6 = 0